168.75t^2-30t+1=0

Solution for 168.75t^2-30t+1=0 equation:

168.75t^2-30t+1=0

a = 168.75; b = -30; c = +1;
Δ = b2-4ac
Δ = -302-4·168.75·1
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-15}{2*168.75}=\frac{15}{337.5}
=15/337.5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+15}{2*168.75}=\frac{45}{337.5}
=45/337.5
$